Question 1189601
<pre>
{{{"f(x)" = "12,000"(1.08)^x}}}

{{{y = 12000(1.08)^x}}}

{{{y/12000=(1.08)^x}}}

{{{log((y/12000))=log((1.08)^x)}}}

{{{log((y/12000))=x*log((1.08))}}}

{{{log((y/12000))/log((1.08^""))}}}{{{""=""}}}{{{x}}}

Edwin</pre>