Question 1189538


{{{(root(3,10))^(1-2x) > 0.1^(2x+1)}}}............take log of both sides


{{{log((root(3,10))^(1-2x) )> log(0.1^(2x+1))}}}.......note that {{{root(3,10)=10^(1/3)}}}


{{{(1-2x) *log((10^(1/3)))> (2x+1)*log(0.1)}}}......{{{0.1=1/10}}}


{{{(1-2x)/ (2x+1)> log(1/10)/log((10^(1/3)))}}}


{{{(1-2x)/ (2x+1)> (log(1)-log(10))/((1/3)log((10)))}}}.......{{{log(1)=0}}}, {{{log(10)=1}}}


{{{(1-2x)/ (2x+1)> (0-1)/((1/3)*1)}}}


{{{(1-2x)/ (2x+1)> -1/(1/3)}}}

{{{(1-2x)/ (2x+1)> -3}}}

{{{1-2x> -3(2x+1)}}}

{{{1-2x> -6x-3}}}

{{{6x-2x> -1-3}}}

{{{4x> -4}}}

{{{x>-1}}}