Question 1189473
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8 times "AB" is equal to "ACA".<br>
Since 8 is even, the last digit of the product, A, must be even.<br>
So the possibilities are
8*(2B)=2C2
8*(4B)=4C4
8*(6B)=6C6
8*(8B)=8C8<br>
The only one of those that has any possible solutions is the first.  So A is 2. (8 times 4B is at most 8*49<400; and similarly for A=6 or A=8....)<br>
So 8*(2B)=2C2; and the product 8*(2B) is at least 8*20=160 and at most 8*29=232.<br>
Finally, 8*29=232 is the only multiple of 8 greater than 200 and less than or equal to 232 that has units digit 2.  So 8*29=232 is the solution to the given multiplication problem.<br>
ANSWER: A*B*C=2*9*3=54<br>