Question 1189247
Given: △АВС, m∠ACB = 90° CD ⊥ AB , m∠ACD = 30°, AC = 8 cm Find: Perimeter of △ABC
<pre>AC, the shorter leg of ΔABC is given as 8 cm.
BC, the longer leg of ΔABC = {{{matrix(1,2, 8sqrt(3), "cm.")}}}
AB, the hypotenuse of △ABC = 2(8) = 16 cm.
Perimeter of △ABC = {{{highlight_green(matrix(1,4, 8 + 8sqrt(3) + 16, "=", 24 + 8sqrt(3), cm))}}}