Question 1189347
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Part (a)


<font color=red>Answer: 5/8</font>


Reason: 
There are 5 red balls out of 8 balls total (5 red+ 3 white = 8 total)


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Part (b)


<font color=red>Answer: 5/14</font>


Reason: 
5/8 is the previous probability mentioned of getting red. 
Assuming the ball is <u>not</u> put back, this means we have 4 red and 7 left over. 
So 4/7 is the probability of getting another red.


Therefore, (5/8)*(4/7) = 20/56 = 5/14 represents getting two red in a row without replacement.


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Part (c)


<font color=red>Answer: 15/56</font>


Reason:
3/8 is the probability of getting white on the first draw (3 white out of 8 total)
5/7 is the probability of getting red on the second draw, assuming the first ball is not put back. 
Multiply the fractions mentioned
(3/8)*(5/7) = 15/56


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Part (d)


<font color=red>Answer: 2/7</font>


Reason:
We're told that the first selection is white. So we have 3-1 = 2 white left out of 7 left over. 
Therefore, 2/7 is the probability of getting a second white <u>given</u> the first is white. 
We do not multiply like we did with parts (b) and (c), simply because we only have one fraction to work with here. 
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