Question 112530
LET X, (X+1) & (X+2) BE THE 3 CONSECUTIVE NUMBERS.
2X^2=38+(X+1)(X+2)
2X^2=38+X^2+3X+2
2X^2-X^2-3X-38-2=0
X^2-3X-40=0
(X-8)(X+5)=0
X-8=0
X=8 ANSWER. 8+1=9 8+2=10.
X+5=0
X=-5 ANSWER. -5+1=-4 -5+2=-3.
PROOF
2(8)^2=38+(9*10)
2*64=38+90
128=128
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2(-5)^2=38+(-4*-3)
2*25=38+12
50=50