Question 1189293
<pre>

AE ≅ DE
ΔAED is isosceles
m∠EDA = m∠EAD
m∠ADC = m∠DAE = 90<sup>o</sup>
m∠EDA + m∠ADC = m∠EAD + m∠DAE
m∠EDC = m∠EAB
∠EDC ≅ ∠EAB

Edwin</pre>