Question 1189287

{{{-2x+2y=-4}}}......eq.1
{{{3x+3y=-18}}}...........eq.2
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you have linear system to solve

first, simplify

{{{-2x+2y=-4}}}......eq.1.......... both sides divide by {{{2}}}
{{{3x+3y=-18}}}...........eq.2,, both sides divide by {{{3}}}
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{{{-x+y=-2}}}......eq.1
{{{x+y=-6}}}...........eq.2
--------------------------------add both

{{{-x+y+x+y=-2-6}}}

{{{2y=-8}}}

{{{y=-4}}}

go to


{{{x+y=-6}}}...........eq.2, substitute {{{y=-4}}}

{{{x-4=-6}}}

{{{x=-6+4}}}

{{{x=-2}}}

solution:

{{{x = -2}}}, {{{y = -4}}}