Question 1189053
<font color=black size=3>
Refer to this page for more info about spherical segments
<a href = "https://mathworld.wolfram.com/SphericalSegment.html">https://mathworld.wolfram.com/SphericalSegment.html</a>


We'll use formula (14) on that page
Plug in a = 31, b = 91, h = 91
a,b are the two radii of each parallel circular face.
h is the height of the spherical segment (aka the distance between the two circular faces)


{{{V = (1/6)*pi*h(3a^2+3b^2+h^2)}}}


{{{V = (1/6)*pi*91(3(31)^2+3(91)^2+(91)^2)}}}


{{{V = (3276637/6)pi}}}


{{{V = 1715643.12128009}}} approximately. I used my calculator's stored version of pi.


The spherical segment has volume of roughly 1,715,643.12128009 cm^3


1 m = 100 cm
(1 m)^3 = (100 cm)^3
1 m^3 = 1,000,000 cm^3
One cubic meter represents 1 million cubic centimeters.
Because of this conversion factor, we'll divide that volume we found earlier by 1,000,000 to convert to cubic meters.


1,715,643.12128009 cm^3 = (1,715,643.12128009/1,000,000) = 1.7156431212801 m^3


The volume of this spherical segment is approximately 1.7156431212801 m^3


1 cubic meter = 1600 kg
1.7156431212801*1 cubic meter = 1.7156431212801*1600 kg
1.7156431212801 cubic meter = 2745.02899404817 kg


<font color=red>Answer: Approximately 2745.02899404817 kg</font>
For the sake of comparison, a small car weighs about 1700 kg
</font>