Question 1189179
The sum of two numbers is 25. The sum of their reciprocals is 1/4. Determine the two numbers.
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x+y = 25  --> y = 25-x
{{{1/x + 1/y = 1/4}}}
{{{(x + y)/xy = 1/4}}}
{{{4x + 4y = xy}}}
Sub for y
{{{4x + 4(25-x) = x*(25-x) = 25x - x^2}}}
{{{100 = 25x - x^2}}}
{{{x^2 - 25x + 100 = 0}}}
*[invoke solve_quadratic_equation 1,-25,100]
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5 and 20