Question 1189170
Assuming it is:
{{{(3c / (c^2-25)) * ((c-5) / (6c^2-3c)) / (2 / (c+5))}}}
right away we can see that it is undefined if c = -5, we get division by 0 in two of the fractions
rewrite this to
{{{(3c / (c^2-25)) * ((c-5) / (6c^2-3c)) * ((c+5)/2)}}}
simplify
{{{(3c / (c-5)(c+5)) * ((c-5) / 3c(2c-1)) * ((c+5)/2)}}}
Cancel c-5, c+5 and 3c
{{{1 * (1/(2c+1)) * (1/2)}}} = {{{1/2(2c+1)}}}
c = -.5 also makes it undefined