Question 1189052
Find the volume of the solid formed when a circular sector of radius 6 cm and angle of 30° is revolved about its angle bisector. 
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Find the height of the spherical segment:
h = 6 - 6*cos(15) =~ 0.204445
{{{Vol = 2pi*r^2h/3}}}
Vol =~ 15.41479 cc
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{{{cos(15) = (sqrt(6) + sqrt(2))/4}}} if you want an exact solution.
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You can split it into a cone and a spherical segment and do it that way, but it's more work.