Question 1189143





1) median position: {{{(31+1)/2 = 16}}}

{{{15}}} are below {{{10}}}, so {{{16}}}th would be the first one to be greater than/equal to {{{10}}} which is {{{10.1}}}

2) {{{median = 12}}} of {{{9}}} values

So {{{5}}}th value is {{{12}}}

{{{7,9,11,12,13,14,17,19}}} are the other {{{ 8}}} values

To find the last measurement, use{{{ mean = 12}}}

{{{Sum = 12*9 = 108}}}

{{{7+9+11+12+13+14+17+19+x = 108}}}

{{{102 + x = 108}}}

{{{x = 6}}}

Answer:

1) {{{10.1}}}

2) {{{6 }}}and {{{12}}}