Question 1189115
Two lines L1 :2y-3x-6=0and L2 :3y+x-20=0 intersect at point A. A third line L3 is perpendicular to L2 at point A. Find the equation of L3 
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Find the coordinates of point A.
Find the slope of L2, call it m1.
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The slope of lines perpendicular to L2 have a slope of -1/m1, call it m.
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Use y-y1 = m(x - x1) where (x1,y1) is point A.
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I don't need the practice.
This is basic, know it.