Question 1189117
Given that {{{a=3}}} and {{{b=5 }}}and {{{c=-1/2 }}}

Evaluate:

{{{((4a)^2+2b-4c)/(1/(4(b^2-3a)))}}}


={{{((4*3)^2+2*5-4(-1/2))/(1/(4(5^2-3*3)))}}}


={{{(144+10+2)/(1/(4(25-9)))}}}


={{{156/(1/64)}}}


={{{156*64}}}


={{{9984}}}