Question 1189116
find the intersection point.
From L2, x=20-3y
so 2y-60+9y-6=0 by substitution
11y=66
y=6
x=2
They intersect at (2, 6)
L2 equation is also y=(-1/3)x+20/3
slope of the desired line is negative reciprocal of -1/3 or 3
point slope formula is y-y1=m (x-x1),m slope,(x1, y1) point
y-6=3(x-2)
y=3x or y=3x+0.

{{{graph(300,300,-10,10,-10,10,1.5x+3,6,3x,(-1/3)x+(20/3))}}}