Question 1189121
Solve for the unknown in the equation below
{{{1-y/2-2((y-3)/2)=0}}}

In the third term of this equation, we are multiplying by 2 and dividing by 2. Thus we can cancel them out.

{{{1-y/2-(y-3))=0}}}

Now we should move all of our 'y' variables to one side. By adding (y/2) and (y-3) to both sides we will have 

{{{1=y/2+(y-3)}}}

We now can break up the parentheses as we've simplified them as far as we can. After this will we add 3 to both sides, this way we only have terms involving 'y' on the right.

{{{1=y/2+(y-3)}}} -> {{{1+3 = y/2+y-3+3}}}

After doing this it leaves us with:

{{{4=y/2+y}}

From here we can combine the 'y' terms by making.

{{{y= (2y)/2}}} 

By doing this we can combine terms by adding fractions with common denominators. This will give us:

{{{4=y/2 + 2y/2}}}

simplifying we get:

{{{4=3y/2}}}

From here we solve for y by multiplying by two then diving by three.

{{{ 8/3=y }}} or {{{ y=8/3 }}}