Question 1189020
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A woman has a total of $13,000 to invest. She invests part of the money in an account that pays 11% per year 
and the rest in an account that pays 12% per year. If the interest earned in the first year is $1490 
how much did she invest in each account?
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<pre>
<U>interest</U> + <U>interest</U>       = <U>total interest</U>


0.12*x   + 0.11*(13000-x) = 1490    dollars


0.12x + 1430 - 0.11x = 1490

0.01x = 1490 - 1430 = 60  ====>  x = {{{60/0.01}}} = 6000.


<U>Answer</U>.  $6000 was invested at 12%.  The rest   13000-6000 = 7000 dollars were invested at 11%.


<U>Check</U>.   0.12*6000 + 0.11*7000 = 1490 dollars, total annual interest.   ! Correct !
</pre>

Solved.


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To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.



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