Question 1188941
p = .09 = probability that a randomly selected driver was involved in an accident last year.
q = 1 - .09 = .91 that a randomly selected driver was not involved in an accident last year.
n = 14 = number of drivers randomly selected.
x = 0 to 14 = number of those drivers that were involved in an accident last year.
p(x) = probability that x number of those 14 drivers that were randomly selected were involved in an accident last year.
p(x) = p^x * q^(n-x) * c(n,x)
c(n,x) = n! / (x! * (n-x)!)


you can find 1 minus (p(0) + p(1) + p(2)) or you can find p(3 to `14).


all of p(x) from x = 0 to 14 is shown in the attached excel spreadsheet.


<img src = "http://theo.x10hosting.com/2021/121701.jpg" >


your solution is that the probability that 3 or more drivers were involved in an accident last year is equal to 0.125510973.