Question 1188950
.
A blood pressure test was given to 450 womem ages 20 to 36. 
It showed that their mean systolic blood pressure was 119.4 mm Hg, 
with the standard deviation of 13.2 mm Hg. 
Determine the z-score, to the nearest hundredth, for a woman who had a systolic blood pressure of reading of 110.5 mm Hg.
~~~~~~~~~~~~~~~



<pre>
Use the formula for z-score


    Z = {{{(x - mu)/sigma}}}


where


Z	=	standard score
x	=	observed value
mu	=	mean of the sample
sigma	=	standard deviation of the sample


    Z = {{{(110.5 - 119.4)/13.2}}} = - 0.674.    <U>ANSWER</U>
</pre>

Easy ? - - - That's all.