Question 1188822
In the following problem:

3(x+4)(x+7)

To obtain a correct solution why must you multiply the binomials

Instead of distributing 3 to the first ? If you do this, it comes up incorrect.
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Makes no difference what you do first.
3(x+4)(x+7) = (3x+12)*(x+7) = 3x^2 + 33x + 84
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3(x+4)(x+7) = (x+4)*(3x+21) = 3x^2 + 33x + 84
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3(x+4)(x+7) = 3(x^2+11X+28) = 3x^2 + 33x + 84
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The only possible mistake is to multiply both binomials by 3.