Question 1188720
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_b(x)\ =\ 100\cdot\3^{x/8}]


Where *[tex \Large x\ =\ 0] represents "now".


Then evaluate either *[tex \Large P_b(-2)] or *[tex \Large P_b(22)] depending on whether you mean "2 hours earlier than now" or "2 hours earlier than 24 hours after now"

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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