Question 1188700
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From the description of the problem and the figure...<br>
a+1+4+c=28; a+c=23  [1]
b+4+2+d=28; b+d=22  [2]
c+2+5+e=28; c+e=21  [3]
d+5+3+a=28; d+a=20  [4]
e+3+1+b=28; e+b=24  [5]<br>
Adding [1] through [5]...<br>
2(a+b+c+d+e)=110
a+b+c+d+e=55  [6]<br>
ANSWER: a+b+c+d+e=55<br>
Note we can determine the values of a, b, c, d, and e individually, even though the problem doesn't ask us to.<br>
Combining [1], [2], and [6] gives us e=10;
Then using the figure gives us b=14, d=8, a=12, c=11.<br>