Question 1188666
Since the length is twice the width, let's say the length is {{{2x}}} and the width is {{{x}}}. So we have the equation {{{(2x-4)(x-3)=180}}}. Expanding, we get {{{2x^2-10x-168=0}}}.
 *[invoke complete_the_square 2, -10, -168, "real-solutions"] 
Since the side lengths can't be negative, we discard {{{x=-7}}}, so x must be 12.
Therefore, the area is {{{(2*12)*12=highlight(highlight_green(highlight(288)))}}} ft<sup>2</sup>.