Question 1188616


a line passing through ({{{-3}}}, {{{6}}}) and ({{{3}}}, {{{-2}}})


equation  in slope intercept form:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} y-intercept

use given points to find a slope

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(-2-6)/(3-(-3))}}}

{{{m=-8/6}}}

{{{m=-4/3}}}

so far equation is  {{{y=-(4/3)x+b}}} 

use one point to calculate {{{b}}}

{{{-2=-(4/3)3+b}}} 

{{{-2=-4+b}}} 

{{{-2+4=b}}} 

{{{b=2}}}


 equation is  {{{y=-(4/3)x+2}}} 



{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(3,-2,.12),locate(3,-2,p(3,-2)),
circle(-3,6,.12),locate(-3,6,p(-3,6)),
graph( 600, 600, -10, 10, -10, 10, -(4/3)x+2)) }}}