Question 1188459


{{{y(n)= 1.05y(n-1) +2}}} and {{{y(0) = 3}}}. 

Find an explicit formula for {{{y(n)}}}.

{{{y(n)= 1.05y(n-1) +2}}}..........if {{{y(0) = 3}}}

{{{3= 1.05y(0-1) +2}}}

{{{(3-2)/ 1.05=y(-1) }}}

{{{(3-2)/ 1.05=-y}}}

{{{20/21=-y}}}

{{{y=-20/21}}}


{{{y(n)= 1.05(-20/21)(n-1) +2}}}...........since {{{1.05(-20/21)=-1}}}


{{{y(n)= -(n-1) +2}}}