Question 1188486
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Find a function whose graph is a parabola with vertex (4,-6) and that passes through the point (5,-3).
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<pre>
This function is a quadratic function, and its vetex form is


    y = {{{a*(x-4)^2-6}}}.


The only thing we need is to find the unknown coefficient "a" (the leading term).


For it, we write equation for the given point


    -3 = {{{a*(5-4)^2-6}}}.


Then we have

 
    -3 = a*1^2 - 6

    -3 + 6 = a

     a     = 3.


<U>ANSWER</U>.  The function is a quadratic function  y = {{{3(x-4)^2-6}}}.
</pre>

Solved.