Question 1188453
Sunday, April 2, 2017
7:06 PM

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iv.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p\(m\(y)\)\ =\ 7\(7y^3\,+\,y\,-\,\frac{2}{5}\)\ +\ 5]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p\(m\(-2)\)\ =\ 7\(7(-2)^3\,+\,(-2)\,-\,\frac{2}{5}\)\ +\ 5]


You can do your own arithmetic.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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