Question 1188446
rewrite as y=2(x^2-4x+5)
=2(x^2-2x+4)+2; be careful here as the "4" is preceded by a multiplier of 2, and the constant in the parentheses is therefore 8, and need 2 more outside the parentheses to recover the original equation.
=2(x-2)^2+2
The minimum point is therefore (2, 2), reverse the sign of h, leave the sign of k alone.
{{{graph(300,300,-10,10,-10,10,2x^2-8x+10)}}}

x-value is -b/2a=8/4=2
y-value is therefore 8-16+10=2