Question 112214
let x=hypotenuse, so 20-x="one side" and x-5="other side"


by Pythagoras, (20-x)^2+(x-5)^2=x^2 ___ 400-40x+x^2+x^2-10x+25=x^2


x^2-50x+425=0 ___ use quadratic formula to find x