Question 1188361
given:

{{{RoTo=RbTb+16}}}
{{{ Ro+Rb=1}}} 
{{{To=1}}}
{{{Tb=-6}}}

 Find: {{{Ro}}} and {{{Rb}}} 

{{{RoTo=RbTb+16}}}.......substitute given values {{{ Ro+Rb=1}}} =>{{{ Ro=1-Rb}}},{{{To=1}}}, and {{{Tb=-6}}}

{{{(1-Rb)*1=Rb(-6)+16}}}
{{{1-Rb=-6Rb+16}}}
{{{6Rb-Rb=16-1}}}
{{{5Rb=15}}}
{{{Rb=3}}}

then {{{ Ro=1-Rb}}} is
{{{ Ro=1-3}}}
{{{ Ro=-2}}}