Question 1188333
Without using tables, show that log base 10 of 17 is approximately equal to (2log base 10 of 6 + 3log base 10 of 2).
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log(17) = ~1.23
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(2log base 10 of 6 + 3log base 10 of 2).
2log(6) + 3log(2) = log(36) + log(8) = log(288) = ~2.459
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"Approximately" can be a matter of opinion.
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PS  No tables were used.  I used a calculator, a desk and a chair.