Question 1188217
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Apply these two rules:
1. Each zero b contributes a factor  (x-b)
2. Complex zeros (and roots) always come in conjugate pairs


The zero at 3  contributes  (x-3)
The zero at -2 contributes  (x-(-2)) = (x+2)
The zero at 8+5i and conjugate contribute  (x-8-5i)(x-8+5i)

Multiply all four of these factors, and simplify, to get:

 {{{ g(x) = x^4-17x^3+99x^2+7x-534}}}


But, this function has  g(2) = -244, and the problem states f(2)=244,
thus we need to multiply g(x) by -1, and the final answer is:

  {{{ f(x) = -(x^4-17x^3+99x^2+7x-534) }}}

Note that f(x) is just g(x) flipped across the x-axis (mirror image).
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EDIT 12/1 --  I see (now, after seeing MathTherapy's answer) that the intention was to indicate N=3 as the _DEGREE_ of the polynomial.  I interpreted N=3 as one of the zeros.   Thanks MathTherapy for catching that.