Question 1188078
f varies directly as the square of m and inversely as j.


if f = 36 when m = 2 and j = 10, find the value of f when m = 4 and j = 6.


the formula is f = k * m^2 / j.


when f = 36 and m = 2 and j = 10, the formula becomes:


36 = k * 2^2 / 10.


solve for k to get:


k = 36 * 10 / 2^2 = 90.


k is the constant of variation.
it does not change it's value in the equation, while all the other variables can change their value.


when m = 4 and j = 6, the formula becomes:


f = k * m^2 / j becomes:


f = 90 * 4^2 / 6.


solve for f to get:


f = 240.


that's your solution.