Question 1187850
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i) The velocity function is the first derivative of the displacement function, so *[tex \Large v(t)\ =\ \frac{ds}{dt}].  The acceleration function is the first derivative of the velocity function or the
second derivative of the displacement function, *[tex \Large a(t)\ =\ \frac{dv}{dt}\ =\ \frac{d^2s}{dt^2}].


ii) Set the velocity function equal to 0.125 m/s and solve for *[tex \Large t]


iii) Set the displacement function equal to 3.5 m and solve for *[tex \Large t_{3.5}].  Then evaluate *[tex a\(\Large t_{3.5}\)]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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