Question 1187971
Find f’(t) for f(x) = (3x-4) (4x3  -  x2 + 1)
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Use ^ (Shift 6) for exponents
f(x) = (3x-4)(4x^3 - x^2 + 1) = 12x^4 -19x^3 + 4x^2 + 3x - 4
f'(x) = 48x^3 - 57x^2 + 8x + 3
Sub t for x to find f'(t)