Question 1187881
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Find the leg AC.  It is  {{{sqrt(AB^2-BC^2)}}} = {{{sqrt(5^2-3^2)}}} = {{{sqrt(25-9)}}} = {{{sqrt(16)}}} = 4.


sine is the ratio of the opposite leg to the hypotenuse.


cosine is the ratio of the adjacent leg to the hypotenuse.


tan is the ratio {{{(sine)/(cosine)}}} = the ratio of opposite leg to the adjacent leg.



Having this info from me, do the rest on your own.
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