Question 1187676
<pre>
Let "X" = "EEE"

The number of distinguishable arrangements of BOOKKXPR is 8!/(2!2!) = 10080.

The number of distinguishable arrangements of BOOKKEEPER is 10!/(2!2!3!) = 151200.

The probability is 10080 ways out of 151200 or 10080/151200 which reduces to 1/15.

Edwin</pre>