Question 112241
{{{3x-75x^3=0}}}


First, factor the common factor, which is 3x.

{{{3x(1-25x^2)=0}}}


This factors again as the difference of two squares:
{{{3x(1-5x)(1+5x)= 0}}}

There are three solutions:
3x=0
x=0


1-5x=0
1=5x
x=1/5


1+5x=0
5x=-1
x=-1/5


R^2  Retired from SCC