Question 112241
{{{3x-75x^3=0}}} Start with the given equation




{{{3x(1-25x^2)=0}}} Factor out the GCF {{{3x}}}



{{{3x(1-5x)(1+5x)=0}}} Now factor {{{1-25x^2}}} using the difference of squares


Now set each factor equal to zero:

{{{3x=0}}}, {{{1-5x=0}}}, or {{{1+5x=0}}}



{{{x=0}}}, {{{x=1/5}}}, or {{{x=-1/5}}} Now solve for x in each case


So our solutions are 


{{{x=0}}}, {{{x=1/5}}}, or {{{x=-1/5}}}