Question 1187662

{{{f(x)=8(x-2)^2+9}}}-> it's a parabola opening upward, vertex is at ({{{2}}},{{{9}}})-> {{{x=2}}} axis of symmetry


 the interval(s) on which is increasing: 

{{{2<x<infinity }}}

({{{2}}},{{{infinity}}})

and decreasing: 

{{{-infinity <x<2}}}

({{{-infinity}}}, {{{2}}})