Question 1187578
<br>
The function has zeros at 0 and 1, so the equation is of the form<br>
{{{y=a(x-0)(x-1)}}} or {{{y=a(x)(x-1)}}}<br>
Use the coordinates of the other given point to determine the constant a:<br>
{{{-20=a(5)(5-1)}}}
{{{-20=20a}}}
{{{a=-1}}}<br>
The equation of the parabola is<br>
{{{y=-1(x)(x-1)}}}
{{{y=-1(x^2-x)}}}
{{{y=-x^2+x}}}<br>