Question 1187490
let M be the mean of the male students; F the mean of the female students.
Ho: M=F
Ha:M NE F;they are unequal
alpha=0.05 p{reject Ho|Ho true}
test statistic is a t(0.975, df=48) 
critical value can be looked up for that test statistic. Reject if |t| > 2.01
Compute the value where t=(M-F)/sqrt ((sdM^2/25)+(sdF^2/25)
or get the pooled variance and the denominator is sp * sqrt ((1/n1)+(1/n2)). Some use it, others don't.
Compare with critical value.
Reject the null hypothesis; the two are different OR fail to reject the null hypothesis, insufficient evidence to say the two are different.