Question 1187472
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Find the slope-intercept form for the line perpendicular to  2x-3y=-6 and passing  through  (4, -9)
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Find the slope-intercept form for the line perpendicular to  Ax+By=C and passing  through  (p, v).
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Slope-intercept form is a form {{{y=mx+b}}}

Slope of given line is {{{-A/B}}}.  A line perpendicular to it will have slope {{{B/A}}}.


For perpendicular line to contain the point (p,v),
{{{Bx-Ay=Bp-Av}}}

{{{-Ay=-Bx+Bp-Av}}}

{{{y=(B/A)x+(Bp-Av)/(-A)}}}

{{{y=(B/A)x-Bp/A+v}}}

{{{highlight_green(y=(B/A)x+(v-Bp/A))}}}


You can apply a similar process for your given equation and point, and simplify, putting into slope intercept form; or you can just substitute the values from your problem description into the formula just derived.