Question 1187452


{{{y=x^3-2x^2-5}}}

 to complete the table {{{x=-3}}} to {{{5}}}


{{{x}}}|{{{y}}}

{{{-3}}}|{{{-50}}}..........{{{y=(-3)^3-2(-3)^2-5=-50}}}

{{{-2}}}|{{{-21}}}..........{{{y=(-2)^3-2(-2)^2-5=-21}}}

{{{0}}}|{{{-5}}}..........{{{y=(0)^3-2(0)^2-5=-5}}}

{{{1}}}|{{{-6}}}..........{{{y=(1)^3-2(1)^2-5=-6}}}

{{{2}}}|{{{-5}}}..........{{{y=(2)^3-2(2)^2-5=-5}}}

{{{3}}}|{{{4}}}..........{{{y=(3)^3-2(3)^2-5=4}}}

{{{4}}}|{{{27}}}..........{{{y=(4)^3-2(4)^2-5=27}}}

{{{5}}}|{{{70}}}..........{{{y=(5)^3-2(5)^2-5=70}}}