Question 1187328
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A bus driver forgets to stop at a bus stop. Just as he passes the stop, he begins to decelerate. 
Five seconds later, the bus is 80m beyond the stop and has slowed to 10 m/s. 
a) Calculate the speed of the bus as it passed the bus stop 
b) What was the deceleration of the bus?
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<pre>
In 5 seconds decelerating, the bus covered 80 meters.


Hence, the bus average speed vas 80/5 = 16 m/s  during this time interval.


Since the speed was changed LINEARLY as the function of time (! uniform deceleration !),
the speed of the bus before decelerating was 32 m/s.


It is the <U>ANSWER</U> to question (a).



Deceleration of the bus was  32 m/s : 5 seconds = {{{32/5}}} = 6 {{{2/5}}}  m/s^2 = 6.4 m/s^2.


It is the <U>ANSWER</U> to question (b).
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