Question 1187212
Expanded, {{{(x - 2/x)^6 }}} is a polynomial with 7 terms.
It has terms in {{{X^6}}} , {{{x^4}}} , {{{x^2}}}, {{{x^0}}} (an independent term), {{{x^(-2)}}}, {{{x^(-4)}}}, y {{{x^(-6)}}} .
The independent term in that polynomial is
{{{20(x^3)(-2/x)^3=20(-2)^3=20(-8)=-160}}} .
The term in {{{x^2}}} in that polynomial is {{{15(x^4)(-2/x)^2=15(4)x^2=60x^2}}}
The independent term in the product {{{ (2 + 3/x^2) (x - 2/x)^6 }}} would be
{{{2(-160)+(3/x^2)(60x^2)=-320+3(60)=-320+180=-140}}}