Question 1187340

If {{{cos(theta)=-3/5}}}=> {{{adj=-3}}} and {{{hyp=5}}}

then 
{{{opp=sqrt(5^2-(-3)^2)}}}
{{{opp=sqrt(16)}}}
{{{opp=4}}} or {{{opp=-4}}}

so, {{{sin(theta)=4/5}}} or {{{sin(theta)=-4/5}}}

since {{{cos(pi/2-theta)=sin(theta)}}}, we have

{{{cos(pi/2-theta)=4/5}}} or {{{cos(pi/2-theta)=-4/5}}}