Question 1187320
How do you solve (sin120+2cos120)/ sec300 without using a calculator and using special values?
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There is nothing to be solved - no variable, no unknowns.
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It can be evaluated.
(sin(120) + 2cos(120))/sec(300) = (sin(120) + 2cos(120))*cos(300)
= ((sqrt(3)/2) + 2*(-0.5))*0.5
= (sqrt(3)/2) - 1)*0.5
= sqrt(3)/4 - 0.5