Question 1187326
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To answer first question, solve this quadratic equation

    -4.9t^2 + 211t + 276 = 0

and use its greatest (positive) root.




To answer second question, you should know from the given height equation

that the gravity acceleration is  g = 4.9*2 = 9.8 m/s^2,  the initial velocity is v = 211 m/s, and starting height is h = 276 m.


Then the maximum height is  {{{H[max]}}} = {{{v^2/(2g)}}} + {{{h}}} = {{{211^2/(2*9.8)}}} + {{{276}}} = 2547.48 meters.    <U>ANSWER</U>
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